Question

Factorise 1 - 4a^2 + 4ab - b^2​

Answer 1

Step-by-step explanation:

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Answer 2

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to factorise:

$1 - 4 {a}^{2} + 4ab - {b}^{2}$

taking 4 common.....

$- 4( {a}^{2} - ab - {b}^{2} \div 4) + 1$

we have the identity formed of a-b whole square...

$- 4({a - \frac{b}{2} )}^{2} + 1$

$1 - ( {2}^{2} )( {a - \frac{b}{2}) }^{2}$

we have the identity formed that is a²-b² which is equal to(a+b)(a-b)

$(1 + 2(a - \frac{b}{2} )(1 - (2)(a - \frac{b}{2} )$

simplifying.....

$(1 + 2a - b)(1 - 2a + b)$

these are the 2 factors....

hope this helps ........

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