Question

The density of ice is 0.918 g/cm3 and hat of water is 1.03 g/cm3.An iceberg floats with a portion of 224 m3 outside the surface of water. The total volume of iceberg is

Answer 1

Dear Student,

◆ Answer -

V0 = 2060 m^3

● Explanation -

# Given -

d = 1.03 g/cm^3 = 1030 kg/m^3

d0 = 0.918 g/cm^3 = 918 kg/m^3

V = 224 m^3

# Solution -

Fraction of outside part to total volume of i1cebeeg is -

V/V0 = 1 - d0/d

224/V0 = 1 - 918/1030

224/V0 = 112/1030

V0 = 224×1030/112

V0 = 2060 m^3

Hence, total volume of iceberg is 2060 m^3.

Thanks dear. Hope this helps you...

Answer 2

The total volume of the iceberg is V = 2060 m^3

Explanation:

Density of ice ρ = 0.918 g/cm^3

Density of water ρ = 1.03 g/cm^3

Let volume of the ice berg = Vm^3

Volume of water displaced V' = ( v - 224 )m^3

Weight of ice berg = weight of water displaced

Vρg = V'ρ'g'

V x 0.918 x 10^3 x g = ( v - 224 ) x 1.03 x 10^3 x g

V ( 1.03 - 0.918 ) = 224 x 1.03

V = 2060 m^3

Thus the total volume of the iceberg is V = 2060 m^3

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