Question

factorise.
(1)4p² - 9q² (2) 25a² - 4b² + 28bc - 49c²

Answer 1

1) 4p²= 2x2xpxp
- 9q²= -3x3xqxq
2) 25a²=5x5xaxa
- 4b²=2x2xbxb
+ 28bc=2x2x7xbxc
- 49c²=-7x7xcxc
 
now i hope u factors these

Answer 2

GIVEN=>

(1)4p² - 9q²

(2) 25a² - 4b² + 28bc - 49c²

to find=>

1)4p² - 9q²

(2) 25a² - 4b² + 28bc - 49c

this factorise

Solution=>

(1)

=4p² - 9q²

$4p {}^{2} = 4 \times p \times p \\ - 9q {}^{2} = - 9 \times q \times q$

----------------------------------:

(2)

=25a² - 4b² + 28bc - 49c

$= > 25a {}^{2} = 5 \times 5 \times a \times a \\ = > - 4b {}^{2} = 4 \times b \times b \\ = > + 28bc = 2 \times 2 \times 7 \times b \times c \\ = > - 49c = 7 \times 7 \times c$

-----------------------------:

I hope it helps