Question

factorise:1-64a^3-12a+48a^2

Answer 1

(a-b)^3 = a^3 - b^3 - 3a^2b - 3ab^2

(1 - 4a)^3 = 1^3 - 64a^3 - 3(1)^2(4a) + 3(1)(4a)^2

= 1-64a^3-12a+48a^2

after factorization we get (1 - 4a)^3

Answer 2

Hope it helped you! Thank you!

Step-by-step explanation: