Math, asked by nirmalskater7874, 1 year ago

factorise 1-64a^3 and 8a^3-27b^3

Answers

Answered by ahana320
2

Answer:

I) 1-64a^3

=(1)^3-(4a)^3

=(1-4a){(1)^2+1.4a+(4a)^2}

=(1-4a)(1+4a+16a^2)

II)8a^3-27b^3

=(2a)^3-(3b)^3

=(2a-3b){(2a)^2+2a.3b+(3b)^2}

=(2a-3b)(4a^2+6ab+9b^2)

Step-by-step explanation:

According to a^3-b^3.

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