factorise 1-64a^3 and 8a^3-27b^3
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Answer:
I) 1-64a^3
=(1)^3-(4a)^3
=(1-4a){(1)^2+1.4a+(4a)^2}
=(1-4a)(1+4a+16a^2)
II)8a^3-27b^3
=(2a)^3-(3b)^3
=(2a-3b){(2a)^2+2a.3b+(3b)^2}
=(2a-3b)(4a^2+6ab+9b^2)
Step-by-step explanation:
According to a^3-b^3.
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