Question

factorise 1+64x cube​

Answer 1

HeRe Is Your Ans ⤵

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Identity :-

A³ - B³ = (A + B) (A² - AB + B²)

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➡1 + 64X³ = 0

➡(1)³ + (4X)³ = 0

➡(1 + 4X) ( (1)² - 1(4X) + (4X)² ) = 0

➡(1 + 4X) ( 16X² - 4X + 1) = 0

Solve This Then U get Value Of X

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$<marquee > hope it helps u$

Answer 2

Answer:

1 + 64x^3

=(1) ^3 + (4x) ^3

= (1+4x) (1 + 16x^2 - 4x)