Question

factorise (1) a^3 + 27​

Answer 1

Step-by-step explanation:

a^3+b^3=(a+b)(a^2+ab+b^2)

a^3+(3)^3=(a+3)(a^2+3a+(3)^2)

=(a+3)(a^2+3a+9)

Answer 2

Answer:

$( a+3) ( a^2-3a+9)$

Step-by-step explanation:

⇒ We have,

$a^3+27 = a^3 + 3^3\\= ( a + 3) ( a^2 - 3a +9)$

$thanku$