Question

Factorise 1. a2-(2a+3b)2
2. a2-81 (b-c)2
3. 25 (2a-b)2-81b2

Answer 1

Answer:

Step-by-step explanation:

1)a²-(2a+3b)²

=a²-(2a²)+(3b)²2.2a.3b

=a²-4a²+9b²+12ab

=-3a²+9b²+3ab+9b²

=-3a(a+3b)+3b(a+3b)

=(a+3b)(-3a+3b)

=(a+3b)-3(a+b)

2)a²-81(b-c)²

=a²-(9b-9c)²

=[a+(9b-9c)] [a-(9b-9c)]

=(a+9b-9c)(a-9b+9c)

Thankyou....hope it helps u

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