Question

factorise 1-(b-c)^2
the answer is (1+b-c)(1-b+c)
plz explain​​

Answer 1

Answer:

Given equation :- 1 - ( b - c )^2

Method 2

1 - ( b - c )^2

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We know,

( a )^2 - ( b )^2 = ( a - b )( a + b )

Applying the formula given above in the question.

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1^2 - ( b - c )^2

{ 1 - ( b - c ) } { 1 + ( b - c ) }

{ 1 - b + c }{ 1 + b - c }

Therefore, 1 - ( b -c )^2 = ( 1 - b + c )( 1 + b - c )...PLZ MARK ME AS BRAINLIEST

Answer 2

Step-by-step explanation:

use formula

X^2-Y^2=(X+y)×(x-y)

here 1 is X

and (b-c) is y