Question

factorise :
1) (m+2n) (3m+4n) - (2m-3m) (m+2n) + (m +2n)²
2) 10 - 13x - 9x²​

Answer 1

Answer:

(3m-2n) (2m-3n)

= 3m ( 2m-3n) -2n (2m-3n)

= 3m × 2m - 3m × 3n - 2n × 2m + 2n × 3n

= 6m² - 9mn - 4mn + 6n²

= 6m² - 13mn + 6n²

When m = 1, n = -1, we get

(3m -2n ) (2m - 3n)

= 6m² - 13mn + 6n²

= 6 × (1)² - 13 × 1 × (-1) + 6 × (-1)² = 6 + 13 + 6 = 25

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HERE IS THE ANSWER TO YOUR QUESTION!!

We have;

(3m-2n) (2m-3n)

=> 3m ( 2m-3n) -2n (2m-3n)

=> 3m × 2m - 3m × 3n - 2n × 2m + 2n × 3n

=> 6m² - 9mn - 4mn + 6n²

=> 6m² - 13mn + 6n²

When m = 1, n = -1, we get

(3m -2n ) (2m - 3n)

=> 6m² - 13mn + 6n²

= 6 × (1)² - 13× 1× (-1) +6 × (-1)² = 6 + 13 + 6 = 25

HOPE IT HELPED!!