Question

factorise
1)p^4-81
2)a^4-b^4​

Answer 1

Step-by-step explanation:

(p^2)^2-(9)^2

(p^2+9)(p^2-9)

(p^2+9)(p+3)(p-3)

(a^2)^2-(b^2)^2

(a^2+b^2)(a^2-b^2)

a^2+b^2)(a+b)(a-b)

Answer 2

Step-by-step explanation:

1. p^4-81

=(p^2)^2-(3^2)^2

=(p^2-9)(p^2+9)

=((p)^2-(3)^2)(p^2+9)

=(p-3)(p+3)(p^2+9)

2. a^4-b^4

=(a^2)^2-(b^2)^2

=(a^2-b^2)(a^2+b^2)

=((a)^2-(b)^2)(a^2+b^2)

=(a-b)(a+b)(a^2+b^2)