Question

Factorise :
1) x^3+x^2-4x-4
2) x^3+y^3-x-y

Answer 1

SOLUTION

1️⃣

$= > {x}^{3} + {x}^{2} - 4x - 4 \\ = > {x}^{2} (x + 1) - 4(x + 1) \\ = > (x + 1) \: \: ( {x}^{2} - 4)\\(x+1) (x+2) (x-2)$

2️⃣

$= > {x}^{3} + y {}^{3} - x - y \\ = > (x + y)( {x}^{2} - xy + {y}^{2} ) - 1(x + y) \\ = > (x + y)( {x}^{2} - xy + {y}^{2} - 1)$

hope it helps ☺️

Answer 2

1) x^3+x^2-4x-4

2) x^3+y^3-x-y

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