Question

Factorise : 100 - a2- b2 - 2ab​

Answer 1

Answer:

Solution -

♦ 100 - a² - b² - 2ab

= (10)² - (a² + b² + 2ab)

= (10)² - (a + b)²

= [10 + (a + b)] [10 - (a + b)

= (10 + a + b) (10 - a - b)

Answer - (10 + a + b) (10 - a - b)

Identity Used -

♢ a² + b² + 2ab = (a + b)²

♢ a² - b² = (a + b) (a - b)

Note -

(10)² = 100

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Answer 2

Answer:

Question

To factorise

100 - a² - b² - 2ab

Answer

here we are taking (-) subtraction sign as common..

100 - (a² + b² + 2ab)

and as we know a² + b² + 2ab = (a+b)²

and 100 = (10)²

(10)² - (a+b)²

here it is in the form of a² - b² =

(a+b) (a-b)

= (10 + a + b) (10 - a - b)