Question

factorise. 100x^2-81 plz help​

Answer 1

Step-by-step explanation:

100x²-81

=(10x)²-(9)²

=(10x-9)(10x+9)

using a²-b²=(a+b)(a-b)

hope this helps you

Answer 2

Step-by-step explanation:

100x2-81

Final result :

(10x + 9) • (10x - 9)

Step by step solution :

Step 1 :

Equation at the end of step 1 :

(22•52x2) - 81

Step 2 :

Trying to factor as a Difference of Squares :

2.1 Factoring: 100x2-81

Theory : A difference of two perfect squares, A2 - B2 can be factored into (A+B) • (A-B)

Proof : (A+B) • (A-B) =

A2 - AB + BA - B2 =

A2 - AB + AB - B2 =

A2 - B2

Note : AB = BA is the commutative property of multiplication.

Note : - AB + AB equals zero and is therefore eliminated from the expression.

Check : 100 is the square of 10

Check : 81 is the square of 9

Check : x2 is the square of x1

Factorization is : (10x + 9) • (10x - 9)

Final result :

(10x + 9) • (10x - 9)