Question

factorise:
10a(2p+q)^3-15b(2p+q)^2+35(2p+q)

Answer 1

Answer:

Step-by-step explanation:

swers and receive 10 points!

Brainly.in

What is your question?

Secondary SchoolMath 5+3 pts

10a(2p+q)^3-15b(2p+q)^2+35(2p+q)

Report by Aryanverma111 01.02.2018

Answers

Sadikalisait · Helping Hand

Know the answer? Add it here!

Brainly User

Hi there!

10a(2p+q)³ - 15b(2b+q)² + 35(2p+q)

5(2p+q)[2a(2p+q)²+7] - 15b(2b+q)²

5(2p+q)[2a(4p²+4pq+q2²)+7] - 15b(4b²+4bq+q² )

5(2p+q)(8ap²+8apq+2aq²+7) - 15b(4b²+4bq+q² )

5(2p+q)(8ap²+8apq+2aq²+7) - 15b(4b²+4bq+q² )

80ap³+80ap²q+20aq²p+70p+40aqp²+40apq²+10aq³+35q-60b³+60b²q-15bq²

Cheers!

Answer 2

Answer:

Step-by-step explanation:

Taking (2p+q) common from all.

(2p+q) {10a(2p+q)^2-15b(2p+q)+35}

It cannot be solved further as no common can be taken out from it and nor any identity fits in it.

Hope it helps!!