Question

factorise 10x2+xy-21y2​

Answer 1

Answer:

(2x+3y)(5x-7y)

Step-by-step explanation:

10x²+xy-21y²

= 10x²+15xy-14xy-21y²

= 5x(2x+3y)-7y(2x+3y)

= (2x+3y)(5x-7y)

Therefore,

10x²+xy-21y² = (2x+3y)(5x-7y)

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Answer 2

$\huge\sf{Answer:-}$

$= 10x {}^{2} + xy - 21y {}^{2} \\ = 10x {}^{2} + 15xy - 14xy - 21y {}^{2} \\ = 5x(2x + 3y) - 7y(2x + 3y) \\ = (2x + 3y)(5x - 7y)$

So,

$10x {}^{2} + xy - 21y {}^{2} = (2x + 3y)(5x - 7y)$