factorise 121a^2+154ab+49b^2
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Answered by
3
121a²+154ab+49b²
=(11a)²+2×11a×7b+(7b)²
=(11a+7b)²
=(11a+7b)(11a+7b)
=(11a)²+2×11a×7b+(7b)²
=(11a+7b)²
=(11a+7b)(11a+7b)
Answered by
4
yes, very easy type question it is
see, if we use this formula (a+b)²=a²+2ab+b²
now
121a²+154ab+49b²
=(11a)²+2.11a.7b+(7b)²
=(11a+7b)²
= (11a+7b) (11a+7b)
⭐formulas are very important while we do sum⭐
see, if we use this formula (a+b)²=a²+2ab+b²
now
121a²+154ab+49b²
=(11a)²+2.11a.7b+(7b)²
=(11a+7b)²
= (11a+7b) (11a+7b)
⭐formulas are very important while we do sum⭐
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