Question

Factorise:
12y^3– 14y^2- 10y

pls solve it , i will mark as the brainliest
no scams pls​

Answer 1

Answer:taking y common

y(12y^2-14y-10)=0

12^2-14y-10=0

12y^2 +6y-20y-10=0

6y(2y+1) -10(2y+1)=0

(6y-10)(2y+1)=0

y=10/6 = 5/3

y=-1/2

Hope it helps

Step-by-step explanation:

Answer 2

${ {\boxed{\huge {ANSWER}}}}$

$\Rightarrow12y^3-14y^2- 10y=0$

Dividing by y

$\Rightarrow12y^{2} -14y^{}-10=0$

$\Rightarrow12y^{2} -20y+6y -10=0$

$\Rightarrow4y(3y -5)+2(3y -5)=0$

$\Rightarrow(3y -5)+(4y +2)=0$

So the roots are either $\boxed{y=\frac{5}{3}}$  OR $\boxed{y=\frac{1}{2} }$