factorise 14x^2+x-3
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1
Answer:
14
x
2
−
x
−
3
=
(
7
x
+
3
)
(
2
x
−
1
)
The factors are right, but how did I get it? The only reasonable factors for
14
x
2
are
7
x
and
2
x
......and their product gives
14
x
2
. The factors of
−
3
are EITHER
1
and
−
3
OR
3
and
−
1
, so I tried each of them in turn....and happened on the right one. There is undoubtedly a more systematic way of doing this.......
Step-by-step explanation:
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