Question

Factorise 15(2x-3y)2-4 (4x-6y)-16

Answer 1

Answer:(10x-15y+4)(6x-9y-4)

Step-by-step explanation:

I hope the question is 15(2x-3y)²-4 (4x-6y)-16

Let m = 2x - 3y

then the question is 15m²-8m-16

=(5m+4)(3m-4)

=[5(2x-3y)+4][3(2x-3y)-4]

=(10x-15y+4)(6x-9y-4)

Answer 2

Factories form is $15(2x-3y)^2-4(4x-6y)-16= (10x-15y+4)(6x-9y- 4)$

Step-by-step explanation:

Given : Expression $15(2x-3y)^2-4(4x-6y)-16$

To find : Factories the expression ?

Solution :

Re-write the expression as,

$15(2x-3y)^2-4(4x-6y)-16 =15(2x-3y)^2 -8(2x-3y)-16$

Let $a = 2x - 3y$

i.e. $15(a)^2 -8(a)-16$

Applying middle term split,

$=15a^2 -20a+12a-16$

$= 5a(3a - 4) + 4(3a - 4)$

$= (5a + 4)(3a - 4)$

Substitute back the value of a,

= (5(2x-3y) + 4)(3(2x-3y) - 4)

= (10x-15y+4)(6x-9y- 4)

Therefore, factories form is $15(2x-3y)^2-4(4x-6y)-16= (10x-15y+4)(6x-9y- 4)$

#Learn more

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