Factorise 15(2x - y) 2 - 16(2x - y) - 15
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Answered by
43
Let (2x-y) = a
15a² -16a -15
=15a² -25a +9a -15
=5a(3a -5) +3(3a-5)
=(3a-5)(5a+3)
Now, substituting the value of a
[3(2x-y) -5][5(2x-y) +3]
=(6x-3y -5)(10x-5y +3)
15a² -16a -15
=15a² -25a +9a -15
=5a(3a -5) +3(3a-5)
=(3a-5)(5a+3)
Now, substituting the value of a
[3(2x-y) -5][5(2x-y) +3]
=(6x-3y -5)(10x-5y +3)
Answered by
5
15(2x-y)² - 16(2x-y) -15
=15(2x-y²) +15(2x-y) - (2x-y) -15
=15(2x-y)[(2x-y) +15] -[(2x-y) -15]
=[15(2x-y) -1][(2x-y) +15]
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