Question

factorise 16(2p-3q)^2+4(2p-3q)

Answer 1

Answer:

16(2p−3q)^2 −4(2p−3q)

=4(2p−3q) [4(2p−3q)−1]

take 4(2p-3q) common,

=4(2p−3q)(8p−12q−1)