Question

factorise 16 (2p - l )² - 25q²

Answer 1

$16 {(2p - i)}^{2} - 25 {q}^{2}$

$16 {(2p - i)}^{2} - {(5q)}^{2}$

Using the identity,

${x}^{2} - {y}^{2} = (x + y)(x - y)$

$= 16(2p - i + 5q)(2p - i - 5q)$