Question

factorise: 16a^4 + 54a

Answer 1

Hello ,

_____________________


16a4 + 54a = 2a(8a3 + 27)

2a(( 2a)3 + (3)3 ))

a3 + b3 = ( a + b)(a2 + b2 - ab)

2a((2a + 3)(4a2 + 9 - 6a)

= (2a)(2a + 3)(4a2 - 6a + 9)

______________________

Best of Luck

Cheers

# Nikky

Answer 2

Answer:

Hello

____________________________

Step-by-step explanation:

16a^4 -54a

2a(8a^3-27)

use identity =

a^3+b^3=(a+b) (a^2+b^2-ab)

2a(2a^3-3^3)

2a(2a+3) (4a^2+9-6a)

==========================================

HOPE YOU HAVE UNDERSTOOD THIS PROBLEM