Question

Factorise 16a^4-54a please

Answer 1

Answer:

Step-by-step explanation:

16$a^{4} -54a$

$=2a(8a^{3}-27 )$    -  taking 2a common factor

$=2a[(2a)^{3} -3^{3} ]$ - converting to $a^{3}$ - $b^{3}$ form

$=2a[(2a-3)((2a)^{2}-2a*3+3^{2} )]$

$=2a[(2a-3)(4a^{2} -6a+9)]$