Question

factorise -16a² - b² + 4bc - 4c²

Answer 1

Answer:

$16 {a}^{2} - ( {b}^{2} + {(2c)}^{2} - 2.2c.b)$

It's in form of (a-b)^2

$16 {a}^{2} - {(b - 2c)}^{2}$

It's in the form of a^2-b^2

${(4a)}^{2} - {(b - 2c)}^{2}$

$(4a + b - 2c)(4a - b + 2c)$