Factorise 16c^2 -9a^2 -6ab -b^2
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Answer:
(4c+3a+b)(4c-3a-b)
Step-by-step explanation:
16c² - 9a² - 6ab - b²
→ (4c)² - [ (3a)²+ 2×3a×b + (b)² ] ......by using (a+b)² identities
∴ (4c)² - (3a+b)²
Now by using "a² - b²" identities we get,
⇒ (4c+3a+b)(4c-3a-b)
Cheers!!
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