Question

Factorise 16x^2+8x+1​

Answer 1

Hello ❤

$16 {x}^{2} + 8x + 1 \\ 16 {x}^{2} + 4x + 4x + 1 \\ 4x(4x + 1) + 1(4x + 1) \\ (4x + 1)(4x + 1)$

HOPE IT HELPS YOU ☺

Answer 2

$16 {x}^{2} + 8x + 1 = 0 \\ \\ 16 {x}^{2} + 4x + 4x + 1 = 0 \\ \\ 4x(4x + 1) + 1(4x + 1) = 0 \\ \\ (4x + 1) \: \: (4x + 1) = 0 \\ \\ x = \frac{ - 1}{4} \: \: \: \: \: and \: \: \: \: x = \frac{ - 1}{4}$

Hope it helps you.