Question

Factorise: 16x 5 - 144x 3

Answer 1

Answer:

$16x^{5}-144x^{3}=16x^{3}(x+3)(x-3)$

Step-by-step explanation:

$16x^{5}-144x^{3}$

=$16x^{3}\times x^{2}-16x^{3}\times9$

=$16x^{3}(x^{2}-9)$

= $16x^{3}(x^{2}-3^{2})$

=$16x^{3}(x+3)(x-3)$

/* By algebraic identity:

$\boxed {a^{2}-b^{2}=(a+b)(a-b)}$

Therefore,

$16x^{5}-144x^{3}=16x^{3}(x+3)(x-3)$

•••♪

Answer 2

Step-by-step explanation:

$16 x ^{3} \times x ^{2} - 16 \times 9 \\ 16 ^{3} (x - 3 ^{2} ) \\ 16 ^{3} (x - 3)(x + 3)$