Question

Factorise (16y^2-1)+(1-4y)^2

Answer 1

$= (16 {y}^{2} - 1 ) + {(1 - 4y)}^{2} \\ = 16 {y}^{2} - 1 + ( {(1)}^{2} - 2 \times 1 \times 4y + {(4y)}^{2} \\ = 16 {y}^{2} - 1 + 1 - 8y + 16 {y}^{2} \\ = 32 {y}^{2} - 8y$
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Answer 2

Answer:

Step-by-step explanation: