Question

factorise - :2(p-q)²-3(p-q)​

Answer 1

Step-by-step explanation:

2(p-q)^2 -3(p-q)

(p-q) {2( p-q) - 3}

(p-q) ( 2p - 2q -3)

Answer 2

2p^2 + 2q^2 - 4pq - 3p + 3q

first we will make (a-b)^2

(p-q)^2 = p^2 + q^2 -2pq

so 2{p^2 +q^2-2pq}

so it would equal to [2p^2+2q^2-4pq]

now -3(p-q)

-3×p=-3p

-3×(-q)=3q

so ans is

2p^2+2q^2-4pq-3p+3q