Question

factorise 2 root2 x^3 + 27y^3​

Answer 1

Answer:

a=x b= 3y c= 2z

Step-by-step explanation:

x3+27y3+8z3−18xyz=x3+(3y)3+(2z)3−3(x)(3y)(2z)

As a3+b3+c3−3abc=(a+b+c)(a2+b2+c2−ab−bc−b)

⇒(x3+27y3+8z3−18xyz)=(x+3y+2z)(x2+9y2+4z2−3xy−6yz−2zx)

Her a=x;b=3y & c=2z