Math, asked by gurkiratthind, 10 months ago

Factorise 216m^3 -729n^3​

Answers

Answered by appidikushalpcpjsm
3

Answer:

to factorise the above equation we have  

216m^3-27n^3

we can write this as

(6m)^3-(3n)^3

by using the identity we have

a^3-b^3=(a-b)(a^2+b^2+ab)

now,we have

(6m-3n)(36m^2+9n^2+18mn)

Step-by-step explanation:

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