Question

factorise 25 a square -9 B square + 12 BC - 4 c square ​

Answer 1

Answer:

(5a-3b-2c) (5a+3b+2c)

step by step explanation:

25a sq. -9b sq. +12bc - 4c sq.

5a sq. - (3b + 2c) sq.

(5a)sq. - (3b+2c) sq.

(5a -3b -2c)(5a+3b+2c)

Answer 2

$(5a+3b-2c)(5a-3b+2c)$

Step-by-step explanation:

Given:

$25a^2-9b^2+12 bc-4c^2$

$(5a)^2-((3b)^2-2\times 3b\times 2c+(2c)^2)$

We know that

$(a-b)^2=a^2+b^2-2ab$

Using the formula

$(5a)^2-(3b-2c)^2$

We know that

$a^2-b^2=(a+b)(a-b)$

Using the formula

$(5a+3b-2c)(5a-3b+2c)$

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