Question

factorise( 25 x square - 1) + (1 + 5x) whole square​

Answer 1

Answer:

$( {25x}^{2} - 1) + (1 + 5x) \\ = (( {5x})^{2} - ( {1})^{2} ) + (1 + 5x) \\ = (5x + 1)(5x - 1) + (5x + 1) \\ = (5x + 1)(5x - 1 + 1) \\ = (5x + 1) \times 5x \\ = 5x(5x + 1) \: are \: the \: required \: factors.$