Math, asked by AnushreeH3713, 10 months ago

Factorise 256 a raise to 8 minus b raised to 8

Answers

Answered by Anonymous
7
\mathfrak{Answer:-}

\tt{256a^{8} - b^{8}}

=》\tt{(2a)^{8} - (b)^{8}}

=》\tt{((2a)^{4})^{2} - ((b^{4})^{2})}

=》\tt{((2a)^{4} + b^{4}) ((2a)^{4} - b^{4})}

=》\tt{((2a)^{4} + b^{4}) (((2a)^{2})^{2} - ((b)^{2})^{2})}

=》 \tt{((2a)^{4} + b^{4}) ((2a)^{2} + b^{2}) ((2a)^{2} - b^{2})}

=》 \tt{((2a)^{4} + b^{4}) ((2a)^{2} + b^{2}) (2a + b)(2a - b)}

Identity used :

\sf{a^{2} - b^{2} = (a + b)(a - b)}
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