Factorise 25x^2-10x+1 36y^2
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By factorization of \bold{25 x^{2}-10 x+1-36 y^{2}},we get ((5x-1) + 6y) ((5x-1) - 6y)
25 x^{2}-10 x+1-36 y^{2}=(5 x)^{2}-2(5 x)+1^{2}-(6 y)^{2}
We know that by formula, (a-b)^{2}=a^{2}+b^{2}-2ab
(5 x)^{2}-2(5 x)+1^{2} can be written as (5 x-1)^{2}
25 x^{2}-10 x+1-36 y^{2}=(5 x-1)^{2}-(6 y)^{2}
We know that by formula, a^{2}-b^{2}=(a+b)(a-b)
Hence 25 x^{2}-10 x+1-36 y^{2} = ((5x-1) + 6y) ((5x-1) - 6y)
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