factorise 27 x cube-y cube
Answers
Answered by
5
hey there.. here is your answer ☺️
27x³ - y³
= (3x)³ -(y)³
= (3x -y) [(3x)² + 3x*y + y²]
= ( 3x - y) (9x2 +3xy + y²)
hope it helps you
27x³ - y³
= (3x)³ -(y)³
= (3x -y) [(3x)² + 3x*y + y²]
= ( 3x - y) (9x2 +3xy + y²)
hope it helps you
PardhanNaveenTandon:
this is write dear
thanks
hope it helps
thanks ru girl
yes
i think that sums solved with identity a cube - b cube
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Answered by
15
Hay!!
Dear friend -
____________________________________
We use here that formula a³-b³ = (a+b) (a²+ab+b²)
27x³-y³
=> (3x)³-y³
=> (3x-y) (9x²+3xy+y³)
I hope it's help you
Dear friend -
____________________________________
We use here that formula a³-b³ = (a+b) (a²+ab+b²)
27x³-y³
=> (3x)³-y³
=> (3x-y) (9x²+3xy+y³)
I hope it's help you
thanks dear
wlcm
ok
can u solve one sum also
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