Question

Rationalise the denominator 2 root 6- root5/3 root 5- 2root 6

Answer 1

I hope it will help uh .....!!!

Answer 2

Answer: After rationalization of denominator, our expression becomes,

$\dfrac{4\sqrt{30}+9}{21}$

Step-by-step explanation:

Since we have given that

$\dfrac{2\sqrt{6}-\sqrt{5}}{3\sqrt{5}-2\sqrt{6}}$

We need to rationalize the denominator :

$\dfrac{2\sqrt{6}-\sqrt{5}}{3\sqrt{5}-2\sqrt{6}}\times \dfrac{3\sqrt{5}+2\sqrt{6}}{3\sqrt{5}+2\sqrt{6}}\\\\=\dfrac{6\sqrt{30}+4\times 6-15-2\sqrt{30}}{45-24}\\\\=\dfrac{4\sqrt{30}+24-15}{21}\\\\=\dfrac{4\sqrt{30}+9}{21}$

Hence, After rationalization of denominator, our expression becomes,

$\dfrac{4\sqrt{30}+9}{21}$