Math, asked by aineya1, 1 year ago

factorise 27a^2-48b^2

Answers

Answered by Fyzul
30
27a^2-48b^2

=》lets take out 3 as common

=》3(9a^2-16b^2)
Answered by vanshikasethi191
34

Answer:

3(3a-4b)(3a+4b)

Step-by-step explanation:

27a^2-48b^2

= 3(9a^2-16b^2)

= 3[(3a)^2-(4b)^2]

= 3(3a-4b)(3a+4b)

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