factorise 27a^2-48b^2
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Answered by
30
27a^2-48b^2
=》lets take out 3 as common
=》3(9a^2-16b^2)
=》lets take out 3 as common
=》3(9a^2-16b^2)
Answered by
34
Answer:
3(3a-4b)(3a+4b)
Step-by-step explanation:
27a^2-48b^2
= 3(9a^2-16b^2)
= 3[(3a)^2-(4b)^2]
= 3(3a-4b)(3a+4b)
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