Question

factorise 27a^3 +108a^2b+144ab^2+64b^2

Answer 1

${(3a + 4b)}^{3}$

Answer 2

Is the question right??

If the question is 27a³+108a²b+144ab²+64b³

Then the solution will be.

= (9a)³+3(9a)²(4b)+3(9a)(4b)²+(4b)³

= (9a+4b)³

{since a³+3a²b+3ab²+b³=(a+b)³