the near point of hypermetropic eye is 75cm . What is the nature and power of lens required to correct this defect??
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Hello friend!!!
Since it is a hypermetropic eye, then the lens is convex, and the power will be:-
F=75 cm = 0.75 m
P=1/f
= 1/0.75
=1.33 D
Hope it helps :)
rphareeth13337:
Wah wah
ntg leave
Your answer is wrong..
Devendra ,the right answer is 2.66 D. Refer ashwin's answer.
Don't give wrong answers...
sry
didn't mean to... thought it was ryt so gave it
Its ok
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