Math, asked by kabeeryashaswini, 7 months ago

factorise 27a^3 - 2 root 2b^3​

Answers

Answered by rajeevr06
5

Answer:

27 {a}^{3}  - 2 \sqrt{2}  {b}^{3}  =

(3a) {}^{3}  - ( \sqrt{2} b) {}^{3}  =

(3a -  \sqrt{2} b)((3a) {}^{2}  + 3a \times  \sqrt{2} b + ( \sqrt{2} b) {}^{2} ) =

(3a -  \sqrt{2} b)(9 {a}^{2}  + 3 \sqrt{2} ab + 2 {b}^{2} )

Step-by-step explanation:

 {x}^{3}  -  {y}^{3}  = (x - y)( {x}^{2}  + xy +  {y}^{2} )

Answered by parnabhowmick1978
1

Answer:

The answer is in the attachment .....

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