Question

Factorise 27a3+64b3 using the above result

Answer 1

Answer:

here is your answer of this question

Answer 2

SOLUTION:-

Given:

27a³ + 64b³

To find:

Factorise.

Explanation:

$27 {a}^{3} + 64 {b}^{ 3} \\ \\ = > (3 {a})^{3} + (4b) {}^{3}$

Here, formula

=) a³ + b³= (a+b)(a² + b² -2ab)

$= > (3a + 4b)[(3a) {}^{2} + (4b) {}^{2} - 2 \times 3a \times 4b] \\ \\ = > (3a + 4b)(9 {a}^{2} + 16 {b}^{2} - 24ab)$

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