Factorise 27k³+216h³
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Cube root of 27k³ is 3k
Cube root of 216h³ is 6h
a³+b³= (a+b)(a²-ab+b²)
27k³+216h³ = (3k+6h) [(3k)² - 3k.6h + (6h)²]
= (3k+6h) (9k²-18kh+36h²)
The factorized product is:
(3k+6h) (9k²-18kh+36h²)
Cube root of 216h³ is 6h
a³+b³= (a+b)(a²-ab+b²)
27k³+216h³ = (3k+6h) [(3k)² - 3k.6h + (6h)²]
= (3k+6h) (9k²-18kh+36h²)
The factorized product is:
(3k+6h) (9k²-18kh+36h²)
thinkdifferent:
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write the answer and highlight it... Bold (font)
You also have the square and cube signs beside the answer column.. Thanks.. !!!
Thank you
Your most welcome :)
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