Question

FACTORISE : 27X^3 + Y^3 + Z^3 - 9XYZ

Answer 1

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Answer 2

Answer:

30

Step-by-step explanation:

We can use the identity

a^3+b^3+c^3-3abc=(a+b+c)(a^2+b^2+c^2-ab-bc-ca)

= 27x^3 + y^3 + z^3 - 9xyz

=( 3x )^3 + ( y )^3 + ( z )^3 - ( 3x*y*z)

=(3+1+1)( 3^2 + 1^2 + 1^2 - (3*1) - (1*1) - (1*1) )

= 5 ( 9 + 1 + 1 - 3 - 1 - 1)

= 5 ( 11 - 5)

= 5 * 6

= 30