Factorise : 27x^3+y^3+z^3-9xyz
Answers
Answered by
6
Step-by-step explanation:
27x³+y³+z³-9xyz
= (3x)³+(y)³+(z)³-3(3x)(y)(z)
[ identity 8 = x³+y³+z³-3xyz= (x+y+z)(x²+y²+z²-xy-yz-zx)]
=(3x+y+z)[(3x)²+(y)²+(z)²-(3x)(y)-(y)(z)-(z)(3x)]
=(3x+y+z)(9x²+y²+z²-3xy-yz-3xz)
may this answer helps you
pls mark me as brainlist
Similar questions