Question

Factorise 27x^3+y^3+z^3-9xyz

Answer 1

Hey !!!!! ^_^

here is your answer

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${27x}^{3} + {y}^{3} + {z}^{3} - 9xyz \\ \\ {(3x)}^{3} + {(y)}^{3} + {(z)}^{3} - 3.(3x)(y)(z) \\ \\ use \: identity \: {a}^{3} + {b}^{3} + {c}^{3} - 3abc \\ = (a + b + c)( {a}^{2} + {b}^{2} + {c}^{2} - ab - bc - ca) \\ \\ (3x + y + z)( {3x}^{2} + {y}^{2} + {z}^{2} - 3xy - yz - 3zx)$


I HOPE IT WILL HELP You ☺️

Thank you ☺️

Answer 2

Hey! Guys it's your boy het

And it's your answer

27x^3+y^3+z^3-9xyz

(3x)^3+(y)^3+(z)^3-3.(3x)(y)(z)

Using identity a^3+b^3+c^3-3abc

=(A+b+c)(a^2+b^2+c^2-ab-bc-ca)

(3x+y+z)(3x^2+y^2+z^2-3xy-yz-3xz)