factorise 27x²-27x²y+9xy²-y³
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Answer:
27x³-27x²y+9xy²-y³.
(3x)³-3(3x)(y)(3x-y)-y³.
It is in the form of a³-3ab(a-b)-b³=(a-b)³.
a=3x. b=y.
(3x)³-3(3x)(y)(3x-y)-y³=(3x-y)³.
I think this is your answer.
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