factorise 27y3+125z3
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Answer:
(3y-5z)[(9y²+25z²+15yz)]
Step-by-step explanation:
So easy, give it a shot student
27y3+125z3 = (3y)³-(5z)³
= (3y-5z) x [(3y-5z)²+3x(3y)(5z)]
[∵ a³-b³=(a-b)³+3ab(a-b)
=(a-b)[(a-b)²+3ab]
= (3y-5z) x [9y²+25z²-2x(3y)(5z)+3x(3y)(5z)]
= (3y-5z)[9y²+25z²+(3y)(5z)]
= (3y-5z)[(9y²+25z²+15yz)]
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