Math, asked by Ananthumurali, 9 months ago

factorise 27y3+125z3​

Answers

Answered by streetburner
24

Answer:

(3y-5z)[(9y²+25z²+15yz)]

Step-by-step explanation:

So easy, give it a shot student

27y3+125z3 = (3y)³-(5z)³

                    = (3y-5z) x [(3y-5z)²+3x(3y)(5z)]

                                                                         [∵ a³-b³=(a-b)³+3ab(a-b)

                                                                                      =(a-b)[(a-b)²+3ab]

                    = (3y-5z) x [9y²+25z²-2x(3y)(5z)+3x(3y)(5z)]

                    = (3y-5z)[9y²+25z²+(3y)(5z)]

                    = (3y-5z)[(9y²+25z²+15yz)]

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